The mean monthly expenditure of a batch of student is 100 with standard deviation 20 if the expenditure is normally distributed find out the maximum expenditure of those 10% of the students whose expenditure is the lowest
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answer. 10% with lowest expenditure means mean - 1.19*sd = 100-1.19*20 =76.2 10% with highest expenditure = mean + 1.19*sd = 123.8
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