Question

The mean no. of defective apples in tray is 7.8 and the variance is 2.73. find the probability that there are exactly 4 defective apples in the tray. state the assumptions

Answer 1

Answer:

47

Explanation:

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Answer 2

Given:

Mean number of defective apples in tray is 7.8

Variance is 2.7

To find:

The probability that there are exactly 4 defective apples in the tray

Answer:

• Given that, variance is 2.7
• Standard deviation (SD) = √variance = √2.7 = 1.64
• Let us assume that the distribution is normal.
• z = (x - mean)/ SD
• Here x is the number of defective apples in the tray = 4
• z = (4 - 7.8)/1.64 = -2.317
• P (0<z<-2.317) = 0.4898
• P (z=-2.317) = 0
• P (x=4) = 0

Thus, the probability that there are exactly 4 defective apples in the tray is 0.