English, asked by japhetnto, 10 months ago

the mean number of defective apples in tray is 7.8 and the variance is 2.73. find the probabilty that there are exactly four defective apples in the tray

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Answered by Anonymous

1

Answer:

z = (x - mean)/ SD. Here x is the number of defective apples in the tray = 4. z = (4 - 7.8)/1.64 = -2.317. P (0<z<-2.317) = 0.4898

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