Question

the mean of 10 numbers is 32 if one number is excluded then the mean get reduced by 2 determine the excluded number. please solve this question

Answer 1

Mean =(x1+x2+x3-----x10)/10

32=(x1+x2+x3----x10)/10

320=(x1+x2+x3-----x10)

If one number is excluded,mean become 32-2=30

30={(x1+x2+x3-----x10)-x10}/9

270=320-x10

270-320=-x10

-50=-x10

50=x

Then the excluded number is 50

Answer 2

Given that Mean of 10 numbers = 32.

Then the total sum of numbers = 32 * 10

                                                     = 320.


Given that 1 number is excluded, the mean gets reduced by 2.

So, Mean of 9 numbers = 32 - 2

                                        = 30.

Therefore the total sum of numbers = 9 * 30

                                                             = 270.



Therefore the excluded number = 320 - 270

                                                       = 50.


Hence the excluded number = 50.


Hope this helps!