The mean of 10 observations was calculated as 40. It was detected on rechecking that the value of 45 was wrongly copied as 15 . Find the correct mean
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Let terms be x1,x2,x3....................x10
Where x10 is taken 15 wrongly
so, x1+x2+...................x9+15/10= 40
so, x1+x2+..............................x9 = 400-15 =385 ...............(1)
So original mean = x1+x2+.................x9+45/10
By Eqn (1)
Original Mean = 385+45/10
= 430/10
= 43
So, Original Mean is 43.
Where x10 is taken 15 wrongly
so, x1+x2+...................x9+15/10= 40
so, x1+x2+..............................x9 = 400-15 =385 ...............(1)
So original mean = x1+x2+.................x9+45/10
By Eqn (1)
Original Mean = 385+45/10
= 430/10
= 43
So, Original Mean is 43.
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