Question

The mean of 11 numbers is 7. One of the numbers, 13. is deleted. What is the mean of the remaining 10numbers?
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Answer 1

SOLUTION

GIVEN

• The mean of 11 numbers is 7

• One of the numbers 13 is deleted.

TO DETERMINE

The mean of the remaining 10 numbers

EVALUATION

Here it is given that,

the mean of 11 numbers is 7

So the sum of 11 numbers

$= 11 \times 7$

$= 77$

Now One of the numbers 13 is deleted.

So remaining number of numbers = 11 - 1 = 10

Now the sum of the remaining 10 numbers

$= 77 - 13$

$= 64$

Hence the required new mean

$= \displaystyle \: \frac{64}{10}$

$= 6.4$

FINAL ANSWER

The mean of the remaining 10 Numbers

= 6.4

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Answer 2

SOLUTION

GIVEN

The mean of 11 numbers is 7

One of the numbers 13 is deleted.

TO DETERMINE

The mean of the remaining 10 numbers

EVALUATION

Here it is given that,

the mean of 11 numbers is 7

So the sum of 11 numbers

= 11 \times 7=11×7

= 77=77

Now One of the numbers 13 is deleted.

So remaining number of numbers = 11 - 1 = 10

Now the sum of the remaining 10 numbers

= 77 - 13=77−13

= 64=64

Hence the required new mean

= \displaystyle \: \frac{64}{10}=

10

64

= 6.4=6.4

FINAL ANSWER

The mean of the remaining 10 Numbers

= 6.4

$\huge{ \mathfrak{ \purple{ ItzMaira}}}$