The mean of 120 observations was 20. It was later found that one item was mistaken as 25 instead of 15. Find the correct mean.
Answers
Step-by-step explanation:
example of the same question
mean (average) = (The sum S of the observations)/(the number n of observations)
mean (average) = (The sum S of the observations)/(the number n of observations)mean = S/n
mean (average) = (The sum S of the observations)/(the number n of observations)mean = S/n 28 = S/10
mean (average) = (The sum S of the observations)/(the number n of observations)mean = S/n 28 = S/10 28(10) = 10(S/10)
mean (average) = (The sum S of the observations)/(the number n of observations)mean = S/n 28 = S/10 28(10) = 10(S/10)280 = S
mean (average) = (The sum S of the observations)/(the number n of observations)mean = S/n 28 = S/10 28(10) = 10(S/10)280 = SSince equality is symmetric, i.e., if a = b, then b = a, then we have:
mean (average) = (The sum S of the observations)/(the number n of observations)mean = S/n 28 = S/10 28(10) = 10(S/10)280 = SSince equality is symmetric, i.e., if a = b, then b = a, then we have:S = 280
mean (average) = (The sum S of the observations)/(the number n of observations)mean = S/n 28 = S/10 28(10) = 10(S/10)280 = SSince equality is symmetric, i.e., if a = b, then b = a, then we have:S = 280Since it was later discovered that one of the observations which was actually 14 was mistakenly read as 24, then the Sum S is 10 (24 – 14) too much; therefore, the correct mean is found as follows:
mean (average) = (The sum S of the observations)/(the number n of observations)mean = S/n 28 = S/10 28(10) = 10(S/10)280 = SSince equality is symmetric, i.e., if a = b, then b = a, then we have:S = 280Since it was later discovered that one of the observations which was actually 14 was mistakenly read as 24, then the Sum S is 10 (24 – 14) too much; therefore, the correct mean is found as follows:Correct mean = (S – 10)/n
mean (average) = (The sum S of the observations)/(the number n of observations)mean = S/n 28 = S/10 28(10) = 10(S/10)280 = SSince equality is symmetric, i.e., if a = b, then b = a, then we have:S = 280Since it was later discovered that one of the observations which was actually 14 was mistakenly read as 24, then the Sum S is 10 (24 – 14) too much; therefore, the correct mean is found as follows:Correct mean = (S – 10)/n= (280 – 10)/10
mean (average) = (The sum S of the observations)/(the number n of observations)mean = S/n 28 = S/10 28(10) = 10(S/10)280 = SSince equality is symmetric, i.e., if a = b, then b = a, then we have:S = 280Since it was later discovered that one of the observations which was actually 14 was mistakenly read as 24, then the Sum S is 10 (24 – 14) too much; therefore, the correct mean is found as follows:Correct mean = (S – 10)/n= (280 – 10)/10= 270/10
mean (average) = (The sum S of the observations)/(the number n of observations)mean = S/n 28 = S/10 28(10) = 10(S/10)280 = SSince equality is symmetric, i.e., if a = b, then b = a, then we have:S = 280Since it was later discovered that one of the observations which was actually 14 was mistakenly read as 24, then the Sum S is 10 (24 – 14) too much; therefore, the correct mean is found as follows:Correct mean = (S – 10)/n= (280 – 10)/10= 270/10Correct mean = 27