Question

The mean of 16 numbers is 8. If 2 is added to every number what will be the new mean ?

Answer 1

Answer:

18.6

Step-by-step explanation:

Let the sum of the numbers be s.

=> Mean = s / 16

=> 8 = s / 16

=> s = 8 * 16

=> s = 128

To add 2 to every no. ,

2 * 16 = 32

128 + 32 = 160

=> New Mean = 160 / 16

=> New Mean = 10

HOPE IT HELPS.

:)

Answer 2

$\Large{\textbf{\underline{\underline{According\;to\;the\;Questions}}}}$

Assumption

Numbers be :-

$\tt{\rightarrow x_{1} , x_{2} , x_{3} , ....... , x_{16}}$

So,

Mean of the numbers

${\rm \: \: \: \: \: \: \: \: \:=\dfrac{x_{1}+x_{2}+x{3}+...+x_{16}}{16}}$

Therefore,

${\rm \: \: \: \: \: \: \: \: \:=\dfrac{x_{1}+x_{2}+x{3}+...+x_{16}}{16}=8}$

$\tt{\rightarrow (x_{1} , x_{2} , x_{3} , ....... , x_{16})=128.....(1)}$

New number

$\tt{\rightarrow (x_{1}+2) , (x_{2}+2) , (x_{3}+2) , ....... , (x_{16}+2)}$

Mean of new numbers

$\tt{\rightarrow \dfrac{(x_{1}+2)+(x_{2}+2)+(x_{3}+2)+....+(x_{16}+2)}{16}}$

$\tt{\rightarrow \dfrac{(x_{1}+x_{2}+x_{3}+....+x_{16})+32}{16}}$

$\tt{\rightarrow \dfrac{128+32}{16}}$

From Equation (1)

$\tt{\rightarrow \dfrac{160}{16}}$

= 10

New Mean is 10