Math, asked by mariposa12, 10 months ago

the mean of 3 numbers is 40. All the three numbers are different natural numbers. If the lowest is 19 ,what would be the highest possible number of remaining two numbers? ​

Answers

Answered by shadow00758
2

Answer:

Step-by-step explanation:

Let the three numbers be a, b and c.

According to the problem, a = 19

And  

Or  

Which gives 19+b+c = 120

So b+c = 101

Consider b = 100, which gives c = 1 which is not possible because the lowest number allowed is 19.

Consider b = 40 which gives c = 61

Consider b = 71, which gives c = 30

Consider b = 81, which gives c = 20

Among these b = 81 is the highest number.

Therefore, the correct answer is 81.

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