the mean of 3 numbers is 40. All the three numbers are different natural numbers. If the lowest is 19 ,what would be the highest possible number of remaining two numbers?
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Step-by-step explanation:
Let the three numbers be a, b and c.
According to the problem, a = 19
And
Or
Which gives 19+b+c = 120
So b+c = 101
Consider b = 100, which gives c = 1 which is not possible because the lowest number allowed is 19.
Consider b = 40 which gives c = 61
Consider b = 71, which gives c = 30
Consider b = 81, which gives c = 20
Among these b = 81 is the highest number.
Therefore, the correct answer is 81.
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