Question

the mean of 3 numbers is 60 . All the 3 numbers are different natural number. If 2 number are 19 and 49. then, what could be the highest possible value of remaining number​

Answer 1

Answer:

Correct option is

A

81

Let the highest number be y and the middle number be x.

We know that,

Mean=

number of observations

sum of observations

∴ Mean=

3

x+y+z

Given that, Mean =40 and the lowest number =19.

∴40=

3

x+y+19

⇒x+y+19=120

⇒ x+y=120−19=101

⇒ y=101−x

Therefore, for y to be maximum, x should be minimum

Also x>19 [As x is not the smallest]

⇒x=20

Therefore, maximum value y=101−20=81