The mean of 31 observations is60. If the mean of first 16 observations is 58 and that of the last 16 observations is62 find 16th observation
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let the no.be x1,x2,...x31
A/Q
(x1+x2+...+x31)/31=60
x1+x2...+x31=1860
A/Q
(x1+x2+...+x16)/16=58
x1=x2+..+x16=928 (eq1)
(x16+x17+..+x310/16=62
x16+x17...+x31=992 (eq2)
adding 1 and 2
x1+..+2x16+...+x31=1920
2x16=1920-1860
x16=30
A/Q
(x1+x2+...+x31)/31=60
x1+x2...+x31=1860
A/Q
(x1+x2+...+x16)/16=58
x1=x2+..+x16=928 (eq1)
(x16+x17+..+x310/16=62
x16+x17...+x31=992 (eq2)
adding 1 and 2
x1+..+2x16+...+x31=1920
2x16=1920-1860
x16=30
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