the mean of 5 nos is 27 if one number is included the new mean is 25. find the included no
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Step-by-step explanation:
Let the mean of the first five no. be (n)
Given that,
(n1+n2+n3+n4+n5) /5=27
(n1+n2+n3+n4+n5)=135
Also given,
(n1+n2+n3+n4+n5+n6) /6=26
(n1+n2+n3+n4+n5+n6)=156
Then,
Excluded No. =(n1+n2+n3+n4+n5+n6)-(n1+n2+n3+n4+n5)
= 156-135
= 21 Answer....
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