Question

The mean of 5 numbers is 39. If one number is excluded, their mean is 35, find the excluded number

Answer 1

Answer:

Step-by-step explanation:

According to the question:

Mean of 5 numbers is 39,

So,

($x_{1}$+$x_{2}$+$x_{3}$+$x_{4$+$x_{5$)÷5=39

⇒($x_{1}$+$x_{2}$+$x_{3}$+$x_{4$+$x_{5$)=39*5

⇒($x_{1}$+$x_{2}$+$x_{3}$+$x_{4$+$x_{5$)=195      ⇒⇒⇒⇒⇒1

Now, If we remove 1 number then the mean will become 35.

Let the removed number be ($x_{5$)

So,

($x_{1}$+$x_{2}$+$x_{3}$+$x_{4$)÷4=35

⇒($x_{1}$+$x_{2}$+$x_{3}$+$x_{4$)=35*4

⇒($x_{1}$+$x_{2}$+$x_{3}$+$x_{4$)=140 ⇒⇒⇒⇒⇒2

From equation 1 we know that,

($x_{1}$+$x_{2}$+$x_{3}$+$x_{4$+$x_{5$)=195

Putting value of 2 we get,

140+($x_{5$)=195

⇒($x_{5$)=195-140

⇒($x_{5$)=55

Hence the excluded number is 55.

Hope this helped!!!!

Answer 2

Given : The mean of 5 numbers is 39. one number is excluded, their mean is 35,

To Find : excluded number

Solution:

mean of 5 numbers is 39.

=> Sum of 5 numbers = 5x 39

=> Sum of 5 numbers = 195

Let say Number Excluded is N

then Sum of 4 Numbers = 195 - N

Mean of 4 Numbers = 35

Sum of 4 numbers = 4 x 35 = 140

Equating Both

=> 195 - N = 140

=> N = 55

Excluded number = 55

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