the mean of 5 observation is 15 it is the mean of first three observations is 14 and that of the last three observations is 17 find the third observations
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n1+n2+n3+n4+n5=15×5
=75
n1+n2+n3=14×3
=42
n3+n4+n5=17×3
=51
The third observation = (42 + 51) - 75
= 93 - 75
= 18.
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