the mean of 5 observation is 30 if one observation is excluded their mean become 28 then find the excluded number
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Mean = 30
let the excluded number be X
fixi be Y
fi = 5
Y / 5 = 30
Y = 30x5 = 150
b.g.c
(150 - X ) / 4 = 28
150 - X = 112
150 - 112 = X
X = 38
The excluded number is 38.
Hope this helps you.☺☺
let the excluded number be X
fixi be Y
fi = 5
Y / 5 = 30
Y = 30x5 = 150
b.g.c
(150 - X ) / 4 = 28
150 - X = 112
150 - 112 = X
X = 38
The excluded number is 38.
Hope this helps you.☺☺
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