Question

The mean of 5 observations is 16. If the mean
of the first 3 observations is 14 and the mean of
the last three is 17, then, the third observation​

Answer 1

Answer:

13

Step-by-step explanation:

Consider the observation as a , b ,c , d and e

According to question,

(a + b + c + d + e )/5 = 16

=> a + b +c + d + e = 80 ----(1)

_______________________

( a + b + c ) /3 = 14

=> a + b + c = 42 ------(2)

_______________________

(c + d + e ) /3 = 17

=> c + d + e = 51 --------(3)

Adding equation 2 and 3 , we get

a + b + 2c + d + e = 93 ------(4)

Subtracting equation 1 from 4 , we get

c = 13

Answer 2

Answer:

Step-by-step explanation:

Let the five numbers be x1,x2,x3,x4,x5

Mean of five numbers is 16

x1+x2+x3+x4+x5/5=16

x1+x2+x3+x4+x5=80-----1

Mean of first three terms is 14

x1+x2+x3/3=14

x1+x2+x3=42-------2

Mean of last three terms is17

x3+x4+x5/3=17

x3+x4+x5=51-----3

Sub eq2 in eq1

42+x4+x5=80

x4+x5= 38------4

Sub eq4 in eq3

x3+38=51

x3=51-38

=13

x3=13

Therefore third number is 13.

Hope it helps you..........