Math, asked by manjulaboduka1955, 11 months ago

the mean of 5 observqtions X,X+2,X+4.X+6 and X+8 is 11 find the value of x​

Answers

Answered by namanpahuja1
1

Answer:

Step-by-step explanation:

In the file

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Answered by mddilshad11ab
63

\huge{\underline{\purple{\rm{Solution:}}}}

\small{\underline{\green{\rm{Given:}}}}

  • \sf{The\: mean\:of\:5\: observation\:are}
  • \rm{x,\:x+2,\:x+4,\:x+6,\:x+8}
  • \sf{The\: mean\:of\:5\: observation=11}

\small{\underline{\orange{\rm{To\: Find:}}}}

  • \sf{The\: value\:of\:x=?}

\small{\underline{\purple{\rm{According\:to\: above\: information:}}}}

\sf\large{Formula\: used}

\rm{\implies mean=\dfrac{Sum\:of\: total\: Number\:of\: observation}{Total\: Number\:of\: observation}}

\rm{\implies \dfrac{x+x+2+x+4+x+6+x+8}{5}=11}

\rm{\implies \dfrac{6x+20}{5}=11}

\rm{\implies 5x+20=55}

\rm{\implies 5x=55-20}

\rm\bold{\implies \cancel{5}x=\cancel{35}}

\rm\red{\implies x=7}

Hence,

\sf\green{\implies The\: value\:of\:x=7}

\large{\underline{\purple{\rm{Verification:}}}}

  • \rm{putting\:the\: value\:x=7\: here,}

\rm{\implies \dfrac{x+x+2+x+4+x+6+x+8}{5}=11}

\rm{\implies \dfrac{7+7+2+7+4+7+6+7+8}{5}=11}

\rm{\implies \dfrac{55}{5}=11}

\rm\orange{\implies 11=11}

\rm\purple{\implies Hence, Verified}

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