Question

the mean of 6, 10, 11, x, 12, y is 10 also y is 7 more than x find the value of x and y​

Answer 1

$mean = \frac{6 + 10 + 11 + x + 12 + x + 7}{6} = 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{46 + 2x }{6} = 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 46 + 2x = 10 \times6 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 2x = 60 - 46 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 2x = 14 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = x = \frac{14}{2} = 7 \\ x = 7$

Then x=7 AND y=x+7 = 7+7 = 14

x=7 AND y=14

Answer 2

Answer:

Step-by-step explanation:

6+10+11+x+12+y/6=10

39+x+y=60

It's given that

y=x+7(putting the value of y).......(1)

We get,

39+x+x+7=60

2x+46=60

2x=14

x=7

Putting value of "x"in equation'1'

We get,

y=7+7

y=14