Question

the mean of 8 numbers is 12 . five of the numbers are 6 , 8 , 5 , 10 and 28. the remaining three numbers are equal to k.
find
the sum of 8 numbers

Answer 1

Mean of 8 numbers=12

Total observations=8

Sum of total observations=8×12=96

Five observations are=5,6,8,10and 28

Remaing Three observations=k,K,K

Mean=5+6+8+10+28+k+k+k

------------------------------

8

12= 57+3k

-----------

8

=12×8 =57+3k

96=57+3k

96-57=3k

39=3k

39

----- =k

3

k=13

Sum of all 8 numbers= 5+6+8+10+13+13+13+28=96

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Answer 2

Answer:

96 is the sum of the numbers.

Step-by-step explanation:

Explanation:

Given, Mean of 8 number = 12.

and five of the numbers are 6, 8,5,10 and 28.

The remaining three numbers are equal to K.

Step 1:

According to the question,

The remaining three numbers are equal to k

So, the sum of remaining three numbers = k + k + k = 3k.

Now, mean of the 8 numbers = $\frac{Sum of the numbers }{ Total \ number}$

⇒ 12 = $\frac{ 6 + 8 + 5 + 10 + 28 + 3k}{8}$        [12is the value of mean , given in the question ]

⇒96 = 57 + 3k

⇒ k = $\frac{96 - 57 }{3} = 13$

So, the three numbers are equal to 13 .

Therefore, sum of the 8 numbers = 6 +8+5+10+28+ 13+13+13 = 96.

Final answer:

Hence, the sum of 9 numbers is 96.

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