the mean of 8 numbers is 41. the mean of 2 of the numbers is 29.what is the mean of other 6 numbers
Answers
Answered by
6
Let sum of 8 numbers be x
Mean = x/8
41=x/8
X= 328
Let the sum of 2 number be y
Mean = sum/no of number
29 = y/2
Y= 58
So later sum of other 6 number is sum of all except that 2 numbers
=X - Y
= 328-58
=270
So mean of other six numbers
= 270/6
=45
Therfore mean of other six numbers is 45
Hope it may help u!!!!
Mean = x/8
41=x/8
X= 328
Let the sum of 2 number be y
Mean = sum/no of number
29 = y/2
Y= 58
So later sum of other 6 number is sum of all except that 2 numbers
=X - Y
= 328-58
=270
So mean of other six numbers
= 270/6
=45
Therfore mean of other six numbers is 45
Hope it may help u!!!!
Anonymous:
Thank you so much JayaramJR07
Answered by
3
Mean = Total/ Number of numbers
=> Total = Mean×Number of Numbers
Therefore, for 8 numbers:
Total = 8×41 = 328
For 2 numbers:
Total= 2×29= 58
Therefore the total of other six numbers
= 328-58
=270
Therefore,
The mean of other six numbers= 270/6= 45
=> Total = Mean×Number of Numbers
Therefore, for 8 numbers:
Total = 8×41 = 328
For 2 numbers:
Total= 2×29= 58
Therefore the total of other six numbers
= 328-58
=270
Therefore,
The mean of other six numbers= 270/6= 45
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