Question

The mean of a,b,c,d and e is 28. If the mean of a,c and e is 24, find the mean of b and d.​

Answer 1

Answer:

b+d=4

Step-by-step explanation:

a+b+c+d+e=28

a+c+e=24

then

b+c+24=28

b+c=4

Answer 2

${\large{\underbrace{\underline{\bf{Question:-}}}}}$

The mean of a, b, c, d and e is 28. If the mean of a, c and e is 24, find the mean of b and d.​

${\large{\underbrace{\underline{\bf{Answer:-}}}}}$

$Mean = \frac{Sum \: of \: all \: observations}{Total \: number \: of \: observations}$

According to the question,

$28 = \frac{a + b + c + d + e }{5}$

a + b + c + d + e = (28) (5)

a + b+ c + d + e = 140 -----(1)

$24 = \frac{a + c + e}{3}$

a + c + e = (24) (3)

a + c + e = 72 -----(2)

Subtracting equation (1) from (2),

(a + b + c + d + e) - ( a + c + e) = b + d

⇒ 140 - 72

= 68

$Mean = \frac{b + d}{2}$

          = $\frac{68}{2}$

          = 34

∴ Mean of b and d = 34

Hope this helps you! ♡