The mean of a certain number of observations is 32. Find the resulting mean, if each observation is,
Increased by 60%
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let a,b,c,......z be n no
(a+b+......+z)/n=32 =a+b+.....+z=32n
if every obervation increased by 60%
ie 60/100a,60/100b,......,60/100z
so, 60/100(a+b+.....+z)
=(60/100)×32n
=19.2n
(a+b+......+z)/n=32 =a+b+.....+z=32n
if every obervation increased by 60%
ie 60/100a,60/100b,......,60/100z
so, 60/100(a+b+.....+z)
=(60/100)×32n
=19.2n
so ans is 32+19.2n
wrong
the answer is 51.2
increase in 60%=
(32*60/100) +32
(1920/100)+32
19.2+32
51.2....
so 51.2 is the answer...
(32*60/100) +32
(1920/100)+32
19.2+32
51.2....
so 51.2 is the answer...
i got help from AmritaLaasya1
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