The mean of a normal distribution is 120 and its
S.D. is 15, therefore its mean deviation is
approximately
and quartile deviation is
approximately=
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0
Answer:
12 and 10
Step-by-step explanation:
Mean deviation = 4/5 × S.D
= 4/5 × 15
= 12
Quartile deviation = 2/3 × S.D
= 2/3 × 15
= 10
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