Question

The mean of a sample of 6 numbers is 3.2. An extra value of 3.9 is included
in the sample. What is the new mean?​

Answer 1

Answer:

23.1

Step-by-step explanation:

   $\frac{a + b + c +d + e + f}{6} = 3.2\\\\\frac{3.9 + a +b + c +d + e +f }{7} = x\\\\ \\a + b + c +d +e + f = 6 (3.2)\\a + b + c +d +e + f = 19.2\\\\3.9 + a + b + c +d +e +f = 7 (x)\\3.9 + a + b + c +d +e +f = 7x\\ a + b + c +d +e +f = 7x - 3.9 \\\\7x - 3.9 = 19.2\\ 7x = 19.2 +3.9\\ 7x = 23.1\\ x = \frac{23.1}{7} \\ x = 3.3\\\\3.9 + a + b + c +d +e +f = 7x\\3.9 + a + b + c +d +e +f = 7 (3.3)\\3.9 + a + b + c +d +e +f = 23.1$

Therefore, the new mean is 23.1

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