Math, asked by sarahmoses29, 4 months ago

The mean of age of 5 men is 40 years. three of them are of same age and they are exclude. the mean of the remaining two is 25 age of one of the excluded person in years is?​

Answers

Answered by Anonymous
1

Answer:

mean=sum of observations/total no of observations.

mean=40

total no of men=5

hence,sum of observations=40×5=200

3 men are excluded

hence,total no of observations=2

mean of remaining 2=25

hence,sum of remaining 2=25×2=50

sum of observations of excluded 3=200-50=150

mean=150/3=50

Step-by-step explanation:

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Answered by Gurudas03
0

Answer:

Mean = Total of observations / Number of observations

Total of observations = Mean X Number of observations

Total of observations = 40 X 5 = 200

Three excluded numbers are same.

Let the excluded number be X, then total of excluded numbers = X + X + X = 3 X

Mean of 2 numbers = 25

Therefore, Total of 2 numbers = 25 X 2 = 50

Therefore, total of excluded numbers = 200 - 50 = 150

3X = 150

therefore X = 150/3 = 50

Age of one of the excluded person in years = 50 years

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