the mean of fiirst n natural numbers is _
Answers
Answer:
Step-by-step explanation:
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The natural numbers are 1,2,3,4,5,. . . . . .
now we will see the sum of natural numbers
sum of first 3 natural numbers= 1+2+3=6
the above can be written as
sum of first 3 natural numbers= 1+2+3=6=3(3+1)/2
sum of first 4 natural numbers= 1+2+3+4=4(4+1)/2
then sum of n natural numbers=1+2+3+......n terms=n(n+1)/2
then the average formula = sum of elements/no of elements
the average of n natural numbers= sum of elements/ no of elements
=(n(n+1)/2)/n
=n(n+1)/2xn
=(n+1)/2
THE AVERAGE OF FIRST N NATURAL NUMBERS=(n+1)/2
The average of first 5 natural numbers
sum of 5 natural numbers=1+2+3+4+5=15
no of elements = 5
average = 15/5 =3
by formula = average of first 5 natural numbers = (n+1)/2 =(5+1)/2
hope u get the answer
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=6/2
=3
Hope it helps..