Question

the mean of first n odd natural number is n²÷18​

Answer 1

Answer: 81

Step-by-step explanation:

Since, First n odd integers are:

1,3,5,...(2n−1)

this sequence forms an AP.

∴1+3+5+...(2n−1) = n/2 ​[1+2n−1]=n^2

[∵Sn = n/2 [n+l]]

Mean = 1+3+5+...+(2n−1)/ n

=n^2/ 81 = n^2/n

= 1/81 = 1/n

= 1/n

= n=81