Math, asked by madhumady, 4 months ago

the mean of first n square numbers​

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Answered by shubham4226
0

Answer:

The average of first n natural numbers = (n+1)/2. The average of squares of first n natural numbers = (n+1)(2n+1)/6. The average of cubes of first n natural numbers = n(n+1)2/4. The average of odd numbers from 1 to n = (last odd number+1)/2.

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