the mean of five consecutive intezers is a. what is the sum of next 15 consecutive intezers interms of a?
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Answer:
Let 1st number =n
The 2nd. 3rd, 4th and 5th numbers must correspondingly be::
n+1, n+2, n+3 & n+4
Thus the sum of the five (5) consecutive numbers (A) = n+(n+1)+(n+2)+(n+3)+(n+4)
Or:
A = 5n + 10 ………eqn.(1)
From equation (1)
n = (A - 10)/5 ……eqn(2)
Let the next five (5) consecutive numbers 6th, 7th, 8th, 9th & 10th be as follows;
n+5, n+6, n+7, n+8 & n+9
Let the sum of theses 5 consecutive numbers be B
Thus B = 5n + 35 ..,,…eqn(3)
Substitute (A-10)/5 from eqn(2) for n in eqn(3)
Hence
B = 5((A-10)/5)+35 …….eqn(4)
Hence:
B = A + 25
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