Question

the mean of five consecutive intezers is a. what is the sum of next 15 consecutive intezers interms of a?
​

Answer 1

Answer:

Let 1st number =n

The 2nd. 3rd, 4th and 5th numbers must correspondingly be::

n+1, n+2, n+3 & n+4

Thus the sum of the five (5) consecutive numbers (A) = n+(n+1)+(n+2)+(n+3)+(n+4)

Or:

A = 5n + 10 ………eqn.(1)

From equation (1)

n = (A - 10)/5 ……eqn(2)

Let the next five (5) consecutive numbers 6th, 7th, 8th, 9th & 10th be as follows;

n+5, n+6, n+7, n+8 & n+9

Let the sum of theses 5 consecutive numbers be B

Thus B = 5n + 35 ..,,…eqn(3)

Substitute (A-10)/5 from eqn(2) for n in eqn(3)

Hence

B = 5((A-10)/5)+35 …….eqn(4)

Hence:

B = A + 25