Question

The mean of five number is 18.0n excluding one number,the
mean becomes 16.Find
the excluded number.​

Answer 1

Mean is the sum of the numbers to the total number.

We have been given five unknown numbers but their mean is 18.

So, the sum of the five numbers = 18×5 = 90

One number has been excluded. So total number of remaining numbers is 4.The mean becomes 16. So the sum of remaining 4 numbers = 16×4 = 64

So the excluded number = (90 - 64) = 26

So, the excluded number is 26

Answer 2

Answer:

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☯️Here's ur answer...☆☆☆

Step-by-step explanation:

$\huge{ \bf{ \mid{ \green{ \underline{ \overline{ \blue{mean...}}}}}}}$

$\large{ \: given \: mean \: of \: five \: numbers = 18} \\ = > \large{ \red{mean = \frac{sum \: of \: five \: numbers}{5} }} \\ \large{sum \: of \: the \: numbers = mean \times 5} \\ = > \large{ sum = 5 \times 18 = 90} \\ \large{ \green{one \: number \: is \: excluded}} \\ \\ \large{given \: new \: mean = 16} \\ = > \large{ \red{new \: mean = \frac{sum \: of \: four \: numbers}{4} }} \\ \large{sum \: of \: rest \: four \: numbers = new \: mean \times 4} \\ \large{ = 16 \times 4 = 64} \\ \large{then \: excluded \: no. = 90 - 64 = 26} \\ (\blue{answer...})$

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