the mean of five number is 27. if one number is excluded , their mean is 26. Find the included number
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Answered by
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(sum of five numbers)/5 = 27
(sum of five numbers)= 135
(sum of 4 numbers)/4 = 26
sum of 4 numbers = 104
the excluded number = 135-104 = 31
(sum of five numbers)= 135
(sum of 4 numbers)/4 = 26
sum of 4 numbers = 104
the excluded number = 135-104 = 31
demon2001:
or you wrote the question wrong...
thanks for ur answer
ur welcome....
if the mean will be 25 after excluding a number then the excluded number will be 35...
ya
hmm
now i remember in my fair notebook sir was cange the question
okkk
gud night
gud nyt.
Answered by
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let the nos be x1,x2,x3,x4,x5
sum of these/5
= 27
therefor by cross multiplication
sum of the nos. = 27*5= 135
now let the excluded no be x5
thus,x1+x2+x3+x4/4=26
again by cross multiply
sum of these/5
= 27
therefor by cross multiplication
sum of the nos. = 27*5= 135
now let the excluded no be x5
thus,x1+x2+x3+x4/4=26
again by cross multiply
what is this
where is the answer
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