Question

The mean of four positive integers is 5
The median of the four integers is 6
.

What is the mean of the largest and smallest of the integers?

Answer 1

Given :  The mean of four positive integers is 5 ,  The median of the four integers is 6

To Find : What is the mean of the largest and smallest of the integers?

Solution:

Let say four numbers  are

A , B  , C , D

arranged in ascending order

A - Smallest

D - Largest

Mean = (A + B + C + D)/4

=> 5 = (A + B + C + D)/4

=> A + B + C + D = 20

Median = ( B + C)/2

=> 6 = (B + C)/2

=> B + C  = 12

=> A + 12 + D  =  20

=> A + D  = 8

=> (A + D)/2 = 4

mean of the largest and smallest of the integers = 4

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