Math, asked by SriKanishK2939, 11 months ago

The mean of four positive integers is 5 . The median of the four integers is 6 . What is the mean of the largest and smallest of the integers

Answers

Answered by AditiHegde
1

Given:  

The mean of four positive integers is 5 and the median of the four integers is 6

To Find:  

What is the mean of the largest and smallest of the integers?

Solution:

Let us consider the 4 numbers be: A, B, C and D  arranged in ascending order .

So, we get, A as the smallest and D as the largest number.

Mean = (A + B + C + D)/4

⇒ 5 = (A + B + C + D)/4

∴ A + B + C + D = 20

Median = ( B + C)/2

⇒ 6 = (B + C)/2

∴ B + C  = 12

⇒ A + 12 + D  =  20

⇒ A + D  = 8

⇒ (A + D)/2 = 4

Therefore, the mean of the largest and smallest of the integers = 4

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