Question

the mean of geometric distribution is​

Answer 1

Answer:

We say that X has a geometric distribution and write X∼G(p) X ∼ G ( p ) where p is the probability of success in a single trial. The mean of the geometric distribution X∼G(p) X ∼ G ( p ) is μ=√1−pp2=√1p(1p−1) μ = 1 − p p 2 = 1 p ( 1 p − 1 ) .

Step-by-step explanation:

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