Question

the mean of observation 5,4,1,12,8,4,8​

Answer 1

Answer:

Let the other two observations be x and y. Then,

Mean=4.4⇒51+2+6+x+y​=4.4⇒x+y=13

Variance=8.24

⇒51​(12+22+62+x2+y2)−(4.4)2=8.24

⇒541+x2+y2​−19.36=8.24

⇒x2+y2+41=138⇒x2+y2=97...(ii)

Now, (x−y)2+(x+y)2

⇒(x−y)2+169=2×97[Using(i)and(ii)]

⇒(x−y)2=25

⇒x−y=5...(iii)

Solving(i)and(iii), we get x=9 and y=4.

Step-by-step explanation:

Answer 2

Answer:

5+4+1+12+8+4+8=42

42÷7=6

6 is the mean