The mean of six numbers is 3 the median is 6. List the numbers
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let the numbers be x1, x2, x3, x4, x5, x6...
it's mean x1 + x2 + x3 + x4 + x5 + x6/ 6 = 3
x1 + x2 + x3 + x4 + x5 + x6 = 18
as median is 6 and number of observation is 6
this implies average of n/2 th and n/2 + 1 th
average of 3rd and 4th term is 6
x3+x4/2 = 6
x3+x4 = 12
x1 + x2 + 12 + x5 + x6 = 18
x1 + x2 + x5 + x6 = 6..
this question is not further solve as question is incomplete..
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