The mean of ten numbers is 55if one number is excluded ,their mean becomes 50 find the excluded number
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Let the number be x
mean of 9 numbers= 50
mean=450/9
mean=50
mean of 10 numbers= 55
m= sum of 10 numbers/10
55=450+x/10
55*10=450+x
x=550-450
x=100
Therefore, number= 100
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Answered by
0
SOLUTION=
LET THE TOTAL SUM BE X
THE MEAN OF 10 NO. IS 55
WE KNOW THAT
MEANS=TOTAL SUM OF GIVEN NO./TOTAL NO.
SO,
X/10=55
X=10×55
X=550
SO TOTAL SUM OF NO. IS 550
AGAIN,
MEAN OF 1 NO. EXCLUDED IS "50"
SO, NOW TOTAL NO. IS "9"
LET THE NEW TOTAL SUM OF NEW MEAN BE "Y"
SO,
Y/9=50
Y=9×50
Y=450
SO NEW MEAN IS 450
NOW TO GET THE EXCLUDED NO.
SUBTRACT 550and 450
550-450
=100
SO THE EXCLUDED NO.IS 100
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protestant:
hi ur answer completed
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