The mean of ten numbers is 58. If one of the numbers is 40, what is the
mean of the other nine?
Answers
The formula for calculating mean is-
(Sum of numbers)/(no. of numbers)
Given, mean of 10 numbers is 58. So,
(N1+N2+N3+N4+ N5+N6+N7+N8+N9+ N10)/10 = 58
(N1+N2+N3+N4+ N5+N6+N7+N8+N9+ N10) = 58*10
One number is given which is 40. Thus,
(N1+N2+N3+N4+ N5+N6+N7+N8+N9+ 40) = 580
(N1+N2+N3+N4+ N5+N6+N7+N8+N9) = 580–40
(N1+N2+N3+N4+ N5+N6+N7+N8+N9) =540
Now there are 9 numbers remaining whose sum is 540. Thus there mean is-
540/9 = 60
Answer:
The formula for calculating mean is-
(Sum of numbers)/(no. of numbers)
Given, mean of 10 numbers is 58. So,
(N1+N2+N3+N4+ N5+N6+N7+N8+N9+ N10)/10 = 58
(N1+N2+N3+N4+ N5+N6+N7+N8+N9+ N10) = 58*10
One number is given which is 40. Thus,
(N1+N2+N3+N4+ N5+N6+N7+N8+N9+ 40) = 580
(N1+N2+N3+N4+ N5+N6+N7+N8+N9) = 580–40
(N1+N2+N3+N4+ N5+N6+N7+N8+N9) =540
Now there are 9 numbers remaining whose sum is 540. Thus there mean is-
540/9 = 60