Question

The mean of ten numbers is 58. If one of the numbers is 40, what is the
mean of the other nine?​

Answer 1

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$The \: formula \: for \: calculating \: mean \: is - \\ \\ </p><p></p><p> \frac{sum \: of \: numbers}{number \: of \: numbers} \\ \\ </p><p></p><p>Given, \: mean \: of \: 10 \: numbers \: is \: 58. \: So, \\ \\ </p><p></p><p> \implies \frac{(N1+N2+N3+N4+ N5+N6+N7+N8+N9+ N10)}{10} = 58\\ \\ </p><p></p><p> \implies(N1+N2+N3+N4+ N5+N6+N7+N8+N9+ N10) = 58*10 \\ \\ </p><p></p><p>One \: number \: is \: given \: which \: is \: 40. \: Thus, \\ \\ </p><p></p><p> (N1+N2+N3+N4+ N5+N6+N7+N8+N9+ 40) = 580 \\ \\ </p><p></p><p> \implies(N1+N2+N3+N4+ N5+N6+N7+N8+N9) = 580–40 \\ \\ </p><p></p><p> \implies(N1+N2+N3+N4+ N5+N6+N7+N8+N9) =540 \\ \\ </p><p></p><p>Now \: there \: are \: 9 \: numbers \: remaining \: whose \: sum \: is \: 540. \: Thus \: there \: mean \: is- \\ \\ </p><p></p><p>\frac{540}{9} = 60\\ \\ </p><p></p><p> \implies \: So \: 60 \: is \: the \: answer.</p><p>$

Note:-

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Answer 2

Step-by-step explanation:

The formula for calculating mean is-

(Sum of numbers)/(no. of numbers)

Given, mean of 10 numbers is 58. So,

(N1+N2+N3+N4+ N5+N6+N7+N8+N9+ N10)/10 = 58

(N1+N2+N3+N4+ N5+N6+N7+N8+N9+ N10) = 58*10

One number is given which is 40. Thus,

(N1+N2+N3+N4+ N5+N6+N7+N8+N9+ 40) = 580

(N1+N2+N3+N4+ N5+N6+N7+N8+N9) = 580–40

(N1+N2+N3+N4+ N5+N6+N7+N8+N9) =540

Now there are 9 numbers remaining whose sum is 540. Thus there mean is-

540/9 = 60