Math, asked by eashwerjamalpur, 11 months ago

The mean of the following data is 21, find the value of p.
Class:- 7.5-12.5, 12.5-17.5, 17.5-22.5 ,22.5-27.5 ,27.5-32.5 ,32.5-37.5
Frequency:- 6, 10 ,P ,10, 2 ,8.

Answers

Answered by maheshv22
8

I think this clippings may help you

Attachments:
Answered by mysticd
2

 \begin {tabular} {|c|c|c|c|} </p><p>\cline {1-4} class&amp; frequency(f_{i} &amp;class mark(x_{i}&amp;\sum f_{i}x_{i} \\</p><p>\cline{1-4} 7.5-12.5&amp;6&amp;10&amp;60 \\</p><p>\cline{1-4} 12.5-17.5&amp;10&amp;15&amp;150 \\</p><p>\cline{1-4} 17.5-22.5&amp;p&amp;20&amp;20p \\</p><p>\cline{1-4} 22.5-27.5&amp;10&amp;25&amp;250 \\</p><p>\cline{1-4} 27.5-32.5&amp;2&amp;30&amp;60 \\</p><p>\cline{1-4} 32.5-37.5&amp;8&amp;35&amp;280\\</p><p>\cline{1-4} - &amp; \sum f_{i}=36+8&amp;-&amp;\sum f_{i}x_{i} = 800+20p \\</p><p>\cline {1-4} </p><p>\end {tabular}

 Mean = 21 \:(given)

 \implies \frac{\sum \f_{i}x_{i}}{\sum f_{i}} = 21

 \implies \frac{800+20p}{36+p} = 21

 \implies 800 + 20p = 21(36+p)

 \implies 800 + 20p = 756 + 21p

 \implies 800 - 756 =  21p - 20p

 \implies 44 =  p

Therefore.,

 \red { Value \:of \: p } \green {= 44}

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