Math, asked by ydhfcnr, 1 year ago

the mean of the following distribution is 53 find the missing frequency class 0-20,20-40,40-60,60-80,80-100 frequency 12,15,32,?,13 find the missing one ​

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Answers

Answered by aiswarya23
91
first we have to find the class marks then multiply the frequency with the class marks then the value we get we have to just substute it...hope it helps
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Answered by hukam0685
5

The missing frequency is 28.

Value of P= 28.

Given:

Class 0-20,20-40,40-60,60-80,80-100

Frequency 12,15,32,P,13

To find: Find the missing frequency P.

Solution:

We know mean of grouped data is given by

\bf \overline x=\frac{\Sigma x_i f_i }{\Sigma f}\\

here,

xi: Class mark of each class.

fi: Frequency of each class

Step 1:

Create table

\begin{tabular}{|c|c|c|c|}\cline{1-4}Class&Freq&x_i&x_if_i\\\cline{1-4}0-20&12&10&120\\\cline{1-4}20-40&15&30&450\\\cline{1-4}40-60&32&50&1600\\\cline{1-4}60-80&P&70&70P\\\cline{1-4}80-100&13&90&1170\\\cline{1-4}Total&72+P&&3340+70P\\\cline{1-4}\end{tabular}\\

Step 2:

Apply the values in formula of mean.

53 =  \frac{3340 + 70P}{72 + P}  \\

or

53(72 + P) = 3340 + 70P \\

or

3816 + 53P = 3340 + 70P \\

or

70P - 53P = 3816 - 3340  \\

or

17P = 476 \\

or

\bf P = 28 \\

The value of missing frequency is 28.

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