the mean of the following frequency distribution is 50.find p
x=10,30,50,70,90.
f=17,5p+3,32,7p-11,19
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sum of observation = 640p +2800
no. of observation = 12p +60
mean=sum of observation / no. of observation
50 = 640p + 2800 / 12p +60
600p + 3000 = 640p + 2800
3000 - 2800 = 640p - 600p
200 = 20p
10 = p
no. of observation = 12p +60
mean=sum of observation / no. of observation
50 = 640p + 2800 / 12p +60
600p + 3000 = 640p + 2800
3000 - 2800 = 640p - 600p
200 = 20p
10 = p
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parthgoel:
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