The mean of the following frequency distribution is 62.8. Find the missing frequency x. Class 0-20 20-40 40-60 60-80 80-100 100-120 Frequency 5 8 x 12 7 8
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Answer: 10
Step-by-step explanation:
- fi= 40+X
- ∑ fixi= 2640+50x
- By direct method Mean = ∑ fixi/ ∑ fi
⇒62.8= 264+50x/40+X
⇒62.8(40-x) = 2640+50x
⇒2512+62.8x = 2640+50x
⇒62.8x - 50x = 2640-2512
⇒12.8x= 128
∴ X= 10
- Hence,the missing frequency is 10.
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