the mean of the following frequency distribution is50find the missing frequencies f1 and f2
Class mark frequency
0-20. 17
20-40 F1
40-60. 32
60-80. F2
80-100. 19
Total. 120
Answers
Answer:The value of f1 is 28 and the value of f2 is 24.
Step-by-step explanation:
The mean of the given data is 50. And the sum of the given frequencies is 120.
This means, 17+f1+32+f2+19=120
f1+f2=52
Therefore f2=52-f1 ----(1)
Now using the value of f2 from (1) in the data.
C.I. Fi xi Fixi
0-20 17 10 170
20-40 f1 30 30f1
40-60 32 50 1600
60-80 52-f1 70 3640-70f1
80-100 19 90 1710
------- ----------
120 7120-40f1
7120-40f1/120=50
7120-40f1=6000
7120-6000=40f1
1120=40f1
f1=28
Now we know f2=52-f1 ==> 52-28=24.
Therefore f1=28; f2=24.
Bro I am attaching a pic so that you can understand it better.
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missing frequencies are 28 n 24