Math, asked by vishwas032, 7 months ago


The mean of the median, the mode and the range of the data:
15, 10. 17. 13. 25. 17. 11, 18, 14, 19. 12. 20 is​

Answers

Answered by Anonymous
2

Answer:

HOPE YOU UNDERSTAND DON'T REPORT PLZ

Step-by-step explanation:

x

10

11

12

13

14

15

f

1

4

7

5

9

8

for a frequency distribution,

So, total number of observation =(1+4+7+5+9+8)=34

It is a even number.

So, median is the value of average of values at (

2

n

)

th

and (

2

n+2

)

th

.

∴ Here, median is the average of the values at (

2

34

)

th

or 17

th

position and (

2

34+2

)

th

or 18

th

position.

x 10 11

12

13

14

15

f

1

4

7

5 9

8

position

1

1+4=5

5+7=12

12+5=17

17+9=26

26+8=34

So, value of x at 17

th

position is 13 and at 18

th

position is 14.

∴Median=(

2

13+14

)=

2

27

=13.5.

Mode for a frequency distribution is the value which is the most common frequent value.

Here 14 has frequency 9 which is highest. So, mode for the frequency distribution is 14.

Answered by RvChaudharY50
2

Solution :-

Arranging the given data in ascending order we get :- 10, 11, 12, 13, 14, 15, 17, 17, 18, 19, 20, 25 = Total 12 .

So,

→ Median = (6th observation + 7th observation)/2

→ Median = (15 + 17)/2 = 16

and,

→ Mode = 17 ( since 17 appears two times.)

and,

→ Range = Highest - Lowest = 25 - 10 = 15

then,

→ Required mean = (Median + Mode + Range)/3

→ Required mean = (16 + 17 + 15)/3

→ Required mean = (48/3)

→ Required mean = 12 (Ans.)

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