Question

the mean of the normal distribution is 500 and 16% of the value is greater then 600 then find the standard deviation of the distribution​

Answer 1

Given : mean of the normal distribution is 500 and 16% of the value is greater then 600

To Find :  the standard deviation of the distribution​

Solution:

Mean = 500

16% of the value is greater then 600

=> 84 % value are less then 600

84 % values refer to Z score = 0.995 ≈ 1

Z score = ( Value - Mean )/ SD

SD = Standard deviation

=> 1 = ( 600  - 500)/SD

=> SD = 100

standard deviation of the distribution​ = 100

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