Math, asked by jyotirastogi274, 1 month ago

the mean of the yellowing data. 2:6 yfind the warne, gee

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Answered by MathCracker
10

Question :-

The mean of following data is 21.6 find the value of p.

Solution :-

Given Data :

</p><p>\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c} \bf f_i&amp; \bf x_i\\ \frac{\qquad \qquad}{} &amp; \frac{\qquad \qquad}{} \\ \sf 5 &amp; \sf 6  \\ \\ \sf 4 &amp; \sf 12 \\ \\ \sf p &amp; \sf 18  \\   \\  \sf6&amp; \sf 24 \\  \\  \sf4&amp; \sf 30 \\  \\  \sf6&amp; \sf 36\end{array}} \\ \end{gathered}\end{gathered}\end{gathered}

Frequency Table :-

 \small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c|c} \bf f_i&amp; \bf x_i&amp; \bf f_i x_i\\ \frac{\qquad \qquad}{} &amp; \frac{\qquad \qquad}{} &amp; \frac{\qquad \qquad}{} \\ \sf 5 &amp; \sf 6 &amp; \sf 5 \times 6 = 30 \\ \\ \sf 4 &amp; \sf 12 &amp; \sf 4 \times 12 = 48\\ \\ \sf p &amp; \sf 18&amp;\sf p \times 18 = 18p \\ \\ \sf 6&amp; \sf 24&amp;\sf 6 \times 24 = 144\\ \\ \sf 4 &amp; \sf 30&amp;\sf 4 \times 30 = 120\\ \\ \sf 6 &amp; \sf 36&amp;\sf 6 \times 36 = 216 \\  \frac{\qquad \qquad}{}  &amp;&amp;\frac{\qquad \qquad}{} \\    \sf  \sum f_i = 25 + p&amp;&amp; \sum  \sf f_i x_i = 558 + 18p\end{array}} \\ \end{gathered}\end{gathered}\end{gathered}

Now,

\sf:\longmapsto{  mean = \frac{\sum f_i x_i}{\sum f_i x_i} }  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \\  \sf : \longmapsto{21.6 =  \frac{558 + 18p}{25 + p} } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \sf : \longmapsto{21.6(25 + p) = 558 + 18p} \\  \\ \sf : \longmapsto{540 + 21.6p = 558 + 18}p \\  \\ \sf : \longmapsto{21.6p - 18p = 558 - 540} \\  \\ \sf : \longmapsto{3.6p = 18}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \\ \sf : \longmapsto{p =  \frac{18}{3.6} } \:  \:  \:  \:    \:  \:  \:   \:  \:   \:  \:  \:  \:  \:  \:  \ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \\  \\ \bf : \longmapsto \red{p = 5} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

Verification :-

\sf:\longmapsto{mean =  \frac{558 + 18p}{25 + p} }  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \sf:\longmapsto{21.6 =  \frac{558 +18( 5)}{25 + 5} } \:  \:  \:  \:  \:  \:  \:  \\  \\ \sf:\longmapsto{21.6 =  \frac{558 + 90}{30} } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \sf:\longmapsto{21.6 =  \frac{648}{30} } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:   \:  \:  \:  \:  \\  \\ \sf:\longmapsto{21.6 \times 30 = 648} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \bf:\longmapsto \red{648 = 648} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

{\boxed{\bf{\green{Hence \: Verified \:  ✔}}}}

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