the mean of three different natural number is 40 if the lowest is 19 what could be the highest possible number of remaining two numbers
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let the other two numbers be x and y
ATQ
(x+y+13) / 3 = 40
x + y + 13 = 120
x + y = 120 - 13
x + y = 107
The least natural no. is 1
Putting x = 1
y = 106
Putting y = 1
x = 106
So the highest value of the remaining number could be 106.
ATQ
(x+y+13) / 3 = 40
x + y + 13 = 120
x + y = 120 - 13
x + y = 107
The least natural no. is 1
Putting x = 1
y = 106
Putting y = 1
x = 106
So the highest value of the remaining number could be 106.
amarnathpathakpdk6i5:
that is not the answer
S I am wrong
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