Question

the mean of three distinct natural numbers is 50 if the largest number is 52 and the difference of other two numbers is 2 , then the product of these numbers is

Answer 1

Answer:

Let the highest number be y and the middle number be x.

We know that,

Mean=

number of observations

sum of observations

∴ Mean=

3

x+y+z

Given that, Mean =40 and the lowest number =19.

∴40=

3

x+y+19

⇒x+y+19=120

⇒ x+y=120−19=101

⇒ y=101−x

Answer 2

The product of numbers is 124800

Given :

• The mean of three distinct natural numbers is 50
• The largest number is 52
• The difference of other two numbers is 2

To find :

The product of two numbers

Solution :

Step 1 of 5 :

Find sum of three distinct natural numbers

Here it is given that mean of three distinct natural numbers is 50

So sum of three distinct natural numbers

= 3 × 50

= 150

Step 2 of 5 :

Find sum of smaller two numbers

The largest number is 52

So sum of smaller two numbers

= 150 - 52

= 98

Step 3 of 5 :

Form the equation

Here it is given that difference of other two numbers is 2

Let the numbers are x and x + 2

So by the given condition

x + x + 2 = 98

Step 4 of 5 :

Find the smaller numbers

x + x + 2 = 98

⇒ 2x + 2 = 98

⇒ 2x = 96

⇒ x = 48

So the smaller numbers are 48 and 50

Step 5 of 5 :

Find the product

Hence the required product

= 48 × 50 × 52

= 124800

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