the mean of three numbers is 10. the mean of other four numbers is 12 .Find the mean of all numbers
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Mean = (3*10 + 4*12)/(3+4) = 78/7 = 11.14
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Let the three numbers be x, y and z.
It is given that the mean of three numbers is 10.
So we have,
x+y+z/3 =10
x+y+z=30 .....(1)
Let the other four numbers be a, b, c and d
It is given that the mean of other four numbers is 12.
So we have,
a+b+c+d/4=12
a+b+c+d=48 .....(2)
From (1) and (2) the sum of all numbers is,
x+y+z+a+b+c+d=30+48 = 78
the mean of all seven numbers is 78/7 = 11.14
It is given that the mean of three numbers is 10.
So we have,
x+y+z/3 =10
x+y+z=30 .....(1)
Let the other four numbers be a, b, c and d
It is given that the mean of other four numbers is 12.
So we have,
a+b+c+d/4=12
a+b+c+d=48 .....(2)
From (1) and (2) the sum of all numbers is,
x+y+z+a+b+c+d=30+48 = 78
the mean of all seven numbers is 78/7 = 11.14
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